UGC NET Answer Key Jul 2018by CBSE
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CBSE released scan
copy of OMR sheet as well as answer key at cbsenet.nic.in.
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Date of availability
of official answer key of UGC NET July 2018 by CBSE is 2nd Week of August.
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Candidates can log in
to download answer key in PDF format and check OMR responses for a limited time
only.
UGC NET Answer Key 2018 Challenge – Submit challenge online. If you are
not satisfied with any answer, then log in to link (https://cbsenet.nic.in/).
Pay a fee of Rs 1000 per question through credit / debit card to challenge.
CBSE will refunds fee only if they accept the challenge.
UGC NET 2018 Challenge Response – Submit challenge online. Like above process, you can
challenge recorded response by logging in at cbsenet.nic.in. Fee for this is
also Rs 1000 per question. Mode of fee payment is credit / debit card. Refund
for fee is applicable when CBSE accepts challenge.
The CBSE NET 2018
answer key contains correct answers to all the questions asked in the exam.
Candidates can download the scanned images of the OMR Answer Sheet and answer
key by entering roll number and date of birth in the specified field.
How to Download CBSE UGC NET Answer Key 2018
Students can download
the answer key by following the steps given below:
1.
Visit the UGC NET 2018
official website, which is cbsenet.nic.in and Click on the ‘Login for
Answer Key and Recorded Response Challenge – NET July 2018’ button
appearing on the screen.
2.
After Clicking on this
button, on the Answer Key Page, enter the Application Number and Password to
download the UGC NET Answer Key.
3.
On clicking on the
Login Button, your account information appears on the screen
4.
Choose the ‘View
Answer Keys‘ option to get the official UGC NET Answer Key.
How to Calculate Score?
Candidates can calculate
score as per the specified marking scheme prescribed by CBSE. For every correct
answer, candidates have to add 2 marks and calculate the score by adding the
marks for every correct answer.
The formula to calculate the score – Marks scored = Number of correct answers
x 2.
CBSE NET 2018 Minimum Qualifying Marks
PROCEDURE & CRITERIA FOR DECLARATION OF RESULT:
This will comprise of
following steps:
Step I: The number of
candidates to be qualified (total slots) for Eligibility for Assistant
Professor shall be equal to 6% of the candidates appeared in both the papers of
NET.
Step II: The total slots
shall be allocated to different categories as per the reservation policy of
Government of India.
Step III: In
order to be considered for Both Junior Research Fellowship (JRF) and
Eligibility for Assistant Professor and for Eligibility for Assistant
Professor Only , the candidate must have appeared in both the papers and
secured at least 40% aggregate marks in both the papers taken together for
General (Unreserved) category candidates and at least 35% aggregate marks in
both the papers taken together for all candidates belonging to the reserved
categories (viz., SC, ST, OBC (belonging to Non-Creamy Layer) & PWD) and
Transgenders.
Step IV: The number of
candidates to be declared qualified in any subject for a
particular category is derived as per the following methodology
illustrated below:
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